x^2+(x(x-2)/4)-3/4=0

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Solution for x^2+(x(x-2)/4)-3/4=0 equation:



x^2+(x(x-2)/4)-3/4=0
We calculate fractions
x^2=0
a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{2}=0$

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